Consider the following. E(Y) = E(Y) = YP(Y). y Derive directly the mean of a hypergeometric random variable. (*)(x =) (~) y 1 (-3)(~=) (2) II IF = N N N. N (+) (~2) + (~:) (~) + + (~:) (N) - (N + N) - = 1 n - 1 n n = Let y be a discrete random variable with the probability function p(y). Then the expected value of Y, E(Y), is defined to be y = 0 y = y = 1 (-1)(x-7) n-y (N=1)