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consider the following procedure which is INVALID: x^2-5x+6=12 (x-3)(x-2)=12 x-3=12 or x-2=12 x=15 x=14 so, the solution set is {14,15}. What is wrong with the
consider the following procedure which is INVALID:
x^2-5x+6=12
(x-3)(x-2)=12
x-3=12 or x-2=12
x=15 x=14
so, the solution set is {14,15}.
What is wrong with the above procedure and why?
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