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consider the following procedure which is INVALID: x^2-5x+6=12 (x-3)(x-2)=12 x-3=12 or x-2=12 x=15 x=14 so, the solution set is {14,15}. What is wrong with the

consider the following procedure which is INVALID:

x^2-5x+6=12

(x-3)(x-2)=12

x-3=12 or x-2=12

x=15 x=14

so, the solution set is {14,15}.

What is wrong with the above procedure and why?

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