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Consider the following program, written using C syntax: (1) #include (2) int x = 3; (3) char y = 'z'; (4) void p(){ (5) double

Consider the following program, written using C syntax:

(1) #include

(2) int x = 3;

(3) char y = 'z';

(4) void p(){

(5) double x = 0.5;

(6) printf("%c ",y);

(7) { int y[10];

(8) }

(9) }

(10) void q(){

(11) int y = 55;

(12) printf("%d ",x);

(13) p();

(14) }

(15) main(){

(16) char x = 'x';

(17) q();

(18) return 0;

(19) }

What does this program print, if we assume static scoping? Explain.

What does this program print, if we assume dynamic scoping? Explain.

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