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Consider the following program, written using C syntax: (1) #include (2) int x = 3; (3) char y = 'z'; (4) void p(){ (5) double
Consider the following program, written using C syntax:
(1) #include
(2) int x = 3;
(3) char y = 'z';
(4) void p(){
(5) double x = 0.5;
(6) printf("%c ",y);
(7) { int y[10];
(8) }
(9) }
(10) void q(){
(11) int y = 55;
(12) printf("%d ",x);
(13) p();
(14) }
(15) main(){
(16) char x = 'x';
(17) q();
(18) return 0;
(19) }
What does this program print, if we assume static scoping? Explain.
What does this program print, if we assume dynamic scoping? Explain.
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