Consider the following quasi-linear PDE, x Ju t where the initial condition is + (1+2u) =-u; f (x) = 1. |x|>1 x 1 (2) - {- = 2x, u (x,0) = f (x) 1, 2+x, 2 - x, 1, x < -1 1 x 0 0 < x 1 x > 1 (8) (b) [8 points] At what time tsh and position sh does your parametric solution break down? Hint: you might need to consider negative values of f' (s).