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Consider the following reaction: A- + BH+ HA + B: If the pKa of HA was 7.1 and the pKa of BH+ was 5.3, what

Consider the following reaction: A- + BH+ HA + B: If the pKa of HA was 7.1 and the pKa of BH+ was 5.3, what would be the value of the equilibrium constant to the nearest ones? Hint: Once you write the expression for Keq, you should recognize terms that you can "swap out" with equivalent terms from the Henderson-Hasselbalch equation; this should greatly simplify the math. (answer is 63 but not sure how to get there, plz help)

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