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Consider the following reaction: N_2(g) + 3 H_2(g) 2 NH_3(g) At time zero there are 0.30 M N_2 and 0.45 M H_2. After 75 seconds

Consider the following reaction: N_2(g) + 3 H_2(g) 2 NH_3(g) At time zero there are 0.30 M N_2 and 0.45 M H_2. After 75 seconds have elapsed, the H_2 concentration has fallen to 0.34 M. How much has [N_2] changed after 75 seconds? Use E for scientific notation. Do not enter units as part of your answer.

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