Consider the following system of linear equations. 4x+12y = -24 -&x-20 36 Solve the system by completing the steps below to produce a reduced row-echelon form. R, and R, denote the first and second rows, respectively. The arrow notation (--) means the expression/matrix on the left becomes the expression/matrix on the right once the row operations are performed. (a) For each step below, enter the coefficient for the row operation. The first matrix in Step 1 is the augmented 8 matrix for the given system of equations. $ ? Step 1: DR. R 3 -6 4 12 -24 -8 -20 36 -8-20 36 Step 2: 1 3 -6 1. R + R R -8-20 36 - 12 Step 3: 3 -6 -6 04 12 -3 Step 4: Enter the coefficient for the row operations and the missing entries in the resulting matrix. 0.22**, *R, -6 GO 6:10 -3 (b) Give the solution y-0