Consider the following two equations: (5) 2Cu(H2O62+(aq)+CO32 (aq) =Cu2(OH)2CO3(s)+CO2(g)+11H2O(l) (6) CO32(aq)+nH3O(aq)HnCO3n2(aq)+nH2O(1) If you added HNO3 (a source of H3O+) to a test tube containing Cu2(OH)2CO3. Equation 6 would shift to the which would the concentration of carbonate ions in solution. Equation 5 would then shift to the causing left; increase; right; more Cu2(OH)2CO3 to form right; decrease; left; Cu2(OH)2CO3 to dissolve right; increase; left; Cu2(OH)2CO3 to dissolve right; decrease; right; Cu2(OH)2CO3 to dissolve right; increase; right; more Cu2(OH)2CO3 to form