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Consider the function f (:12) = 45in (1 (:17 3)) + 5. State the amplitude A, period P, and 2 midline. State the phase shift
Consider the function f (:12) = 45in (1 (:17 3)) + 5. State the amplitude A, period P, and 2 midline. State the phase shift and vertical translation. In the full period [0, P], state the maximum and minimum yvalues and their corresponding tit-values. Enter the exact answers. Amplitude: A = Number Period: P = l'u'dline: y = Number The phase shift is Click for Lia - The vertical translation is Click ferList v Hints for the maximum and minimum values of f [rs]: The maximum value of y = sink) is y = 1 and the corresponding :1: values are a: = 1; and 3 multiples of 2 a" less than and more than this :1: value. You may want to solve % (:1: 3) = %. The minimum value of y = SiJl{a:) is y = 1 and the corresponding 2*: values are a: 2 Ti"- and multiples of 2 a" less than and more than this :1: value. You may want to solve E (:1: 3) = 3. 2 2 If you get a value for a: that is less than 0, you could add multiples of P to get into the next cycles. If you get a value for a: that is more than P, you could subtract multiples of P to get into the previous cycles. For a: in the interval [0, P], the maximum y-value and corresponding at-value is at: multiples of 2 7 less than and more than this x value. You may want to solve ? (x - 3) = 3 TI 2 . If you get a value for x that is less than 0, you could add multiples of P to get into the next cycles. . If you get a value for x that is more than P, you could subtract multiples of P to get into the previous cycles. For x in the interval [0, P], the maximum y-value and corresponding x-value is at: Va sin (a) T= Va sin (a) y = For a in the interval [0, P], the minimum y-value and corresponding x-value is at: a a sin (a) ? D sin (a) y =
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