Consider the game of rock-paper-scissors to be an experiment. In the long run, roommate A chooses rock 36% of the time, and roommate B chooses rock 22% of the time; roommate A selects paper 32% of the time, and roommate B selects paper 25% of the time; roommate A chooses scissors 32% of the time, and roommate B chooses scissors 53% of the time. (These choices are made randomly and independently of each other.)

The probabilities were assigned using the .

Define event A as the event that roommate A wins the game and thus does not have to wash the dishes.

What is P(A), the probability of event A?

P(A) = 0.76

P(A) = 0.67

P(A) = 0.22

P(A) = 0.34

Let event C be the event that the game ends in a tie.

What is P(C), the probability of event C?

P(C) = 0.33

P(C) = 0.25

P(C) = 0.86

P(C) = 0.32

Define event B as the event that roommate B wins the game and thus does not have to wash the dishes. What is the probability that roommate B wins the game?

P(B) = 0.33

P(B) = 0.37

P(B) = 0.67

P(B) = 0.50

What is the complement of event A?

AcAc= event B or event C

AcAc= event C

AcAc= event B

AcAc= event A or event C

The probability of AcAcis .