Consider the graph of the following equation ( see figure). V2 = _x(12 - x) 2 36 10/ 8 6 4 2 X 4 8 12 16 20 -2 -4 -6 -8 -10 Find the area of the surface formed when the loop of this graph is revolved about the x-axis. (a) Write the definite integral for finding the indicated surface area. 2 TE dx (b) Explain why the integral does not satisfy the definition of a definite integral. The integrand is not defined at x = 0. The integrand is not differentiable at x = 0. O The integrand is not defined at x = 12. The integrand is not differentiable at x = 12. (c) Use the integration capabilities of a graphing utility to approximate the surface area. (Round your answer to one decimal place.)