Consider the integral I V1 - 22 To derive a formula for this integral, we could use the circle trigonometric substitution 2 - sin(z) Since dx du cos(U) the integral can be easily evaluated as a function of u cos(u) I = / du 1 - sin ? ( 24 ) And finally as a function of the original variable r I - Note: the Maple syntax for cos (a ) is arccos (x)