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Consider the language of expressions with variables E in Exp :: = N T F x E 1 + E 2 E 1 * E

Consider the language of expressions with variables
E in Exp ::= N T F x E1+ E2 E1* E2 E1 E2 E1 E2E1 E1= E2 E1> E2
Encode the type-checking relation in PROLOG as a predicate hastype(G,E,T).

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