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Consider the method below, which is intended to return true if there is at least one duplicate in the vector, and false if there are

Consider the method below, which is intended to return true if there is at least one duplicate in the vector, and false if there are no duplicates.
bool hasdupicate((vectornums))
{{
for((int k=0=0; k << nums.size()1()-1; k++)++)
{{
if((nums[[k]==]==nums[[k+1])+1])
return true;
}}
return false;
}}
Under which condition will the method not necessarily produce the desired result?
Question 2828 options:
A))
When the vector is sorted in decreasing order.
B))
When the vector has at most 22 elements.
C))
When the values in the vector are all positive.
D))
When the vector is sorted in increasing order.
E))
When the values in the vector are all the same.

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The method will not necessarily produce the desired result under option B When the vector has at most 22 elements This is because the loop condition k numssize 1 will not be appropriate for vectors wi... blur-text-image

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