Consider the office layout shown below and the accompanying trip and distance matrices.

Interdepartmental Trips per Day

$(2)(3)(4)(5)(6)(7)(8)$

$(1)1021310412$

$(2)725585$

$(3)31431112$

$(4)191263$

$(5)121$

$(6)311$

$(7)8$

Distances between Departments $($meters$)$

$(2)(3)(4)(5)(6)(7)(8)$

$(1)15304510203550$

$(2)153020102035$

$(3)1540201020$

$(4)60503010$

$(5)103050$

$(6)2040$

$(7)20$

Determine the total distance traveled per day. Do not round intermediate calculations. Round your answer to the nearest whole number.

Determine the layout that results in a lower total distance traveled per day. Do not round intermediate calculations. Round your answer to the nearest whole number. $5,620$ METERS IS THE CORRECT ANSWER.

If you switch departments

$5$ and $8$

$,$ the total distance traveled per day will lower to $\_\_\_\_\_\_\_$ meters.