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Consider the problem Minimizc f(X)=x12+x22+x32+x42 subject to g1(X)=x1+2x2+3x3+5x410=0 g2(X)=x1+2x2+5x3+6x415=0 - Show that by selecting 3 and 4 as independent variables, the Jacobian method fails to
Consider the problem Minimizc f(X)=x12+x22+x32+x42 subject to g1(X)=x1+2x2+3x3+5x410=0 g2(X)=x1+2x2+5x3+6x415=0 - Show that by selecting 3 and 4 as independent variables, the Jacobian method fails to provide a solution and state the reason. - Solve the problem using 1 and 3 as independent variables, and apply the sufficiency condition to determine the type of the resulting stationary point. - Determine the sensitivity coefficients, given the solution in (b). Consider the problem Minimizc f(X)=x12+x22+x32+x42 subject to g1(X)=x1+2x2+3x3+5x410=0 g2(X)=x1+2x2+5x3+6x415=0 - Show that by selecting 3 and 4 as independent variables, the Jacobian method fails to provide a solution and state the reason. - Solve the problem using 1 and 3 as independent variables, and apply the sufficiency condition to determine the type of the resulting stationary point. - Determine the sensitivity coefficients, given the solution in (b)
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