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Consider the problem of determining whether a DFA accepts some string with more 1 s than 0 s . Prove the following language is decidable:

Consider the problem of determining whether a DFA accepts some string
with more 1s than 0s. Prove the following language is decidable: IMBDFA:={D|DisaDFAandL(D)\cap {w|whasmore1sthan0s}!=}

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