Consider the region bounded by the curve f (I) = 4::2 on the interval [2, 4]. Suppose the region is rotated about the m a>tis to form a solid of revolution. We want to nd the volume of the solid and we will work through the following steps: a} Draw a graph of the 2D region. On a separate graph trv to draw the 30 solid. These will help you in the rest of the problem. bi What is the shape of the cross-sections? [59'9\"] V | Q : I c} What is a formula for area of the cross-sections? [59'3\"] V d} Which of the below integrals give the volume of the solid? [SEMI] V 1. f; 1:333:13 ii. 1: 16m\" dim iii. f: wide iv. 1: lm'ds: v. f: lwdem e] What is the volume of the solid? [59'9\"] V A solid of revolution is formed by rotating the region between the graph of f (@) = e" and the c-axis over the interval [-2, 0] around the -axis. Which of the following integrals give the volume of the solid? Q1 e^x -2 Ov= (ex)? dac ov=felt dee ov = net dx Ov = 2 ne da Ov = (, Tell daeA solid of revolution is formed by rotating the region between the graph of g (y) = and the y-axis over 1