Consider this differential equation for y = y(w): (=0 \"3'2 d1: _ 1+2?- Find the general solution, and use it to complete parts (a)(c) below. (3) Find the solution y(a:) for (4:) that satisfies the additional requirement y(0) = 0. Determine the largest open interval containing a: = 0 on which the identity (*) is valid. (Use interval notation to enter your answer; type \"inf\" to represent 00.) a y(m)= I .,form . (b) Repeat part (a), but use the modified initial condition y(0) = 1. 11(3) = ,for :v E . (c) Repeat part (a), but use the modified initial condition y(0) = 6. MS\") = , for :n E . tan(6) + tan() Hint: tan(0+) = W