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Consider two light bulbs that are connected in series to an ideal 9.88 V battery. The current running in the circuit is 8.41 A, and

Consider two light bulbs that are connected in series to an ideal 9.88 V battery. The current running in the circuit is 8.41 A, and the power dissipated in bulb A and bulb B are can be symbolized as PA and PB, respectively. Bulb A dissipates twice as much power as bulb B (i.e., PA / PB = 2).Calculate the resistance, RA, of light bulb A. Give your answer in units of Ohms.

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