Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Considering the below Wireshark capture of hping3 that is to craft attack packets from 10.0.2.4 to victim machine 10.0.2.22, answer the following questions: 1. what

image text in transcribedimage text in transcribed

Considering the below Wireshark capture of hping3 that is to craft attack packets from 10.0.2.4 to victim machine 10.0.2.22, answer the following questions: 1. what is the type of this attack? 2. What is wrong with it? how do you fix it?

image text in transcribed

image text in transcribed

UESTION 23 Considering the below Wireshark capture of hping that is to craft attack packets from 10.0.2.4 to victim machine 10.0.2.22, answer the following questions: 1. what is the type of this attack? 2. What is wrong with it? how do you fix it? File Edit View Go Capture Analyse Statistics Telephony Wireless Tools Help SS NO Source Time Destination Protocol Length Info 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37339 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37340 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 - 37335 [RST, ACK] Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37336 [RST, ACK] Seq=1 Ack=1 Wi... 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37337 [RST, ACK] Seq=1 Ack=1 Wi... 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37341 - O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.22 10.0.2.4 TCP 60 0 37338 [RST, ACK] Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37339 [RST, ACK] Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37340 [RST, ACK) Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37342 - O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37341 [RST, ACK] Seq=1 Ack=1 Wi.. 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37343 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2:4 10.0.2.22 TCP 54 37344 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37345 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37346 O [SYN] Seq=0 Win=512 Len=0 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Close MacBook Air 5437339 O [SYN] Seq=0 Win=512 Len=8 6.2.22 TCP 5437340 - O [SYN] Seq=0 Win=512 Len=0 10.0.2.22 10.0.2.4 TCP 60 0 37335 [RST, ACK] Seq=1 Ack=1 wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 - 37336 [RST, ACK] Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 60 0 - 37337 [RST, ACK] Seq=1 Ack=1 wi... 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37341 O [SYN] Seq=0 Win=512 Len=0 37338 [RST, ACK] Seq=1 Ack=1 wi.. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37339 [RST, ACK] Seq=1 Ack=1 Wi.. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 60 0 7. 1.515... 10.0.2.22 10.0.2.4 TCP 60 0 7... 1.515... 10.0.2.4 37340 [RST, ACK] Seq=1 Ack=1 Wi.. 10.0.2.22 TCP 54 37342 O [SYN] Seq=0 Win=512 Len=6 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37341 [RST, ACK] Seq=1 Ack=1 Wi... 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37343 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37344 [SYN] Seq=0 Win=512 Len=6 O [SYN] Seq=0 Win=512 Len=r 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37345 10.0.2.22 TCP 54 37346 - 0 [SYN] Seq=0 Win=512 Len= 7... 1.515... 10.0.2.4 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37342 [RST, ACK] Seq=1 Ack=1 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37347 O [SYN] Seq=0 Win=512 Leo 7.. 1.516.. 10.0.2.22 10.0.2.4. TCP_60 0. 37343 TRST. ACK1 Seas1 Acka1 Book Pro UESTION 23 Considering the below Wireshark capture of hping that is to craft attack packets from 10.0.2.4 to victim machine 10.0.2.22, answer the following questions: 1. what is the type of this attack? 2. What is wrong with it? how do you fix it? File Edit View Go Capture Analyse Statistics Telephony Wireless Tools Help SS NO Source Time Destination Protocol Length Info 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37339 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37340 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 - 37335 [RST, ACK] Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37336 [RST, ACK] Seq=1 Ack=1 Wi... 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37337 [RST, ACK] Seq=1 Ack=1 Wi... 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37341 - O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.22 10.0.2.4 TCP 60 0 37338 [RST, ACK] Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37339 [RST, ACK] Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37340 [RST, ACK) Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37342 - O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37341 [RST, ACK] Seq=1 Ack=1 Wi.. 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37343 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2:4 10.0.2.22 TCP 54 37344 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37345 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37346 O [SYN] Seq=0 Win=512 Len=0 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Close MacBook Air 5437339 O [SYN] Seq=0 Win=512 Len=8 6.2.22 TCP 5437340 - O [SYN] Seq=0 Win=512 Len=0 10.0.2.22 10.0.2.4 TCP 60 0 37335 [RST, ACK] Seq=1 Ack=1 wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 - 37336 [RST, ACK] Seq=1 Ack=1 Wi. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 60 0 - 37337 [RST, ACK] Seq=1 Ack=1 wi... 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37341 O [SYN] Seq=0 Win=512 Len=0 37338 [RST, ACK] Seq=1 Ack=1 wi.. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37339 [RST, ACK] Seq=1 Ack=1 Wi.. 7... 1.515... 10.0.2.22 10.0.2.4 TCP 60 0 7. 1.515... 10.0.2.22 10.0.2.4 TCP 60 0 7... 1.515... 10.0.2.4 37340 [RST, ACK] Seq=1 Ack=1 Wi.. 10.0.2.22 TCP 54 37342 O [SYN] Seq=0 Win=512 Len=6 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37341 [RST, ACK] Seq=1 Ack=1 Wi... 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37343 O [SYN] Seq=0 Win=512 Len=0 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37344 [SYN] Seq=0 Win=512 Len=6 O [SYN] Seq=0 Win=512 Len=r 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37345 10.0.2.22 TCP 54 37346 - 0 [SYN] Seq=0 Win=512 Len= 7... 1.515... 10.0.2.4 7... 1.515... 10.0.2.22 10.0.2.4 TCP 600 37342 [RST, ACK] Seq=1 Ack=1 7... 1.515... 10.0.2.4 10.0.2.22 TCP 54 37347 O [SYN] Seq=0 Win=512 Leo 7.. 1.516.. 10.0.2.22 10.0.2.4. TCP_60 0. 37343 TRST. ACK1 Seas1 Acka1 Book Pro

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Managerial Accounting

Authors: Susan V. Crosson, Belverd E. Needles

10th edition

1133940595, 978-1133940593

More Books

Students also viewed these Accounting questions