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Correct and complete answer will get upvote and many thanks. Wrong incomplete answer will get downvote. INOTE: Algebraic expressions follow FORTRAN conventions. Use full calculator
Correct and complete answer will get upvote and many thanks. Wrong incomplete answer will get downvote.
INOTE: Algebraic expressions follow FORTRAN conventions. Use full calculator precision for intermediate values. Use the bisection method with the function defined by: A=(X + 0.45) / 2.94 B=(x - 2.49) / 2.94 P1=((A-1)**2)*(1+2*A) P2=((B+1)**2)*(1-2*B) F(X) = (P1 * 2.56) + (P2 * (-7.69)) Start with interval (Xleft,Xright) = (-0.45, 2.49) The function values at these end points are F(xleft) = 2.56 F(Xright) = -7.69 The new approximation interval bracketing the root after ONE bisection is l _5 Function values at these end points 7 and -2.565 The new approximation interval bracketing the root after ONE MORE bisection is ( _8 Function values at these end points are: 0.958437 and __10_ The new approximation interval bracketing the root after ONE MORE bisection is 11_ 12_) If Xmid satisfies the convergence criterior f(Xmid) |Step by Step Solution
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