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Could i please get some assistance with these questions ? thank you. Numbers (2,4,5). from the +-axis. 2. (Knight Problem 22.33) A -12 nC charge
Could i please get some assistance with these questions ? thank you.
Numbers (2,4,5).
from the +-axis. 2. (Knight Problem 22.33) A -12 nC charge is located at (x, y) = (1.0 cm, 0 cm). What are the electric fields at the positions (r, y) = (5.0 cm,0 cm), (-5.0 cm, 0 em), and (0 cm, 5 cm)? Write each electric field vector in compo- ment form. [Answer: -6.8 x 10* { N/C, 3.0 x 10", i N/C. (8.1 x 10 i - 4.1 x 10*j) N/C.] 3.0 c 3. (Knight Problem 23.1) What are the strength and direction of the electric field at the position indicated by the dot in FIGURE EX23.1? Specify the direction as an angle above or below horizontal. [Answer: 7.6 x 103 N/C along the +r- FIG axis.] 7. (Knight Problem 2 30 nc (+ of length L with to 5.0 cm a. Find an expressi P on the axis of the swer: And0 12-1974 5.0 cm b. Verify that your 5.0 cm r L. [Answer: c. Evaluate E at r 3.0 nC (+ [Answer: 9.8 x 10* FIGURE EX23.1 4. (Knight Problem 23.9) A 10-em-long thin glass rod uni- + + formly charged to +10 nC and a 10-cm-long thin plastic rod uniformly charged to -10 nC are placed side by side, 4.0 cm apart. What are the electric field strengths E, to FIGUR Ea at distances 1.0 cm, 2.0 cm, and 3.0 cm from the glass rod along the line connecting the midpoints of the two rods? 8. (Knight Problem 2 [Answer: 2.3 x 10* N/C, 1.67 x 10* N/C, 2.3 x 10* N/C.] along a thin, flexib into the semicircle 5. (Knight Problem 23.35) a. Find an expressi What are the strength and 2.0 cm the semicircle. Hin direction of the electric field -5.0 nC (+10 nC a small angle Au = at the position indicated by the dot in FIGURE P23.35? Give your answer (a) in b. Evaluate the fiel component form and (b) 4.0 cm i Answer: 1.70 x 10 as a magnitude and angle measured ew or cow (spec- ify which) from the posi- 5.0 nC (+ tive r-axis. [Answer: A. (1.0x 10' 1-3.6x10* j) N/C, b. 1.1 x 10" N/C, 19.4" cow FIGURE P23.35 from the +r-axis.]Step by Step Solution
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