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Could i please get some assistance with this, it would mean a lot as i am trying to prepare for a test. Thank you. 1.
Could i please get some assistance with this, it would mean a lot as i am trying to prepare for a test. Thank you.
1. (Knight Problem 23.5) An electric dipole is formed from two charges, 1q, spaced 1.0 cm apart. The dipole is at the ori- gin, oriented along the y-axis. The electric field strength at the point (x, y) = 10 cm, 10 cm) is 360 N/C. a. What is the charge q? Give your answer in nC. [Answer: 2.0 nC.] b. What is the electric field strength at the point (r, y) = (10 cm, 0 cm)? [Answer: 180 N/C.] 2. (Knight Problem 23.15) Two 10-cm-diameter charged rings face each other, 20 cm apart. Both rings are charged to +20 nC. What is the electric field strength at (a) the midpoint between the two rings and (b) the center of the left ring? [Answer: (a) 0 N/C, (b) 4.1 x 10* N/C.] 3. (Knight Problem 23.17) The electric field strength 2.0 cm from the surface of a 10-cm-diameter metal ball is 50,000 N/C. What is the charge (in nC) on the ball? [Answer: 27 nc. 4. (Knight Problem 23.21) A 2.0 m x 4.0 m flat carpet acquires a uniformly distributed charge of -10 /C after you and your friends walk across it several times. A 2.5 mg dust particle is suspended in midair just above the center of the carpet. What is the charge on the dust particle? [Answer: -0.35 PC.] 5. (Knight Problem 23.23) A parallel-plate capacitor is formed from two 6.0-cm-diameter electrodes spaced 2.0 mm apart. The electric field strength inside the capacitor is 1.0 x 10" N/C. What is the charge (in no) on each electrode? [An- swer: 25 nC, -25 nC.]Step by Step Solution
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