Could someone help me with these please? I don't understand how to find the missing boxes and the questions asked.

A. Masses on Top of the Table Mass Position Torque Torque Position Mass About About About About (in) (in) x-axis y-axis X-axis Y-axis | (in) (in) ICT- (gm- in in 04 4000 -400 DO 18 SO 500 500L D-500 -100 Tsa Total Torque 400 500 1-500 Total Torque (100 gm masses) (50 gm masses) 1 in) 100 100 -200 -200 |-400 -150 350 50 50 1 -10 -112 Total Torque (50 gm masses) Total Torque (100 gm masses) 400 500 -500 Total Torque (100 gm masses) 15 * 100 From the first table: Is the sum of the torques about either individual axis equal to zero? If not, where might the discrepancy exist? In Step 3: If the 100 gram mass remains where it is and a 200 gram mass replaces the 50 gram mass, where should the 200 gram mass be moved to achieve rotational equilibrium? B. Masses Suspended from Hangers | Mass Position Mass X Position y (in) (in) (sm) Torque About About x-axisy -axis gm- gm- in in) Torgue About About x-axis y-axis gm- gm- in in) (in) (in) 0 -3 900 3000S 2001 - 40 Total Torque Total Torque Total Torque 16 - 3 500 250 -7 -8 30 600 0 5 400 Total Torque C I C. Center of Gravity of a System of + Masses 1. Mass Position Position Torque | About About X-axis y-axis Mass (m) Torgue About About X-axis y-axis gm- gm- in) in) (in) (in) in in) 7,3 6.2 200 100 30 150 250 -7 -8 Total Torque 2. Determine the theoretical center of gravity for the 100, 150, and 250 gram masses. X. -2.9 -2.5 Theoretical x: -2.9 Theoretical y: -2.5 3. Find the percent error: Measured X:-2.9 in Measure y: -2.8 in % error in x: 0% % error in y: -12% Note: % error = 100 x (theory - measured/ theory) D. Center of Gravity of an Unknown Object 1. Mass of object: m=187 gm Mass Position 4.7 100 100 4.8 3. Calculate the center of gravity for the irregularly-shaped object. Remember to give units. Calculated Calculated you A. Masses on Top of the Table Mass Position Torque Torque Position Mass About About About About (in) (in) x-axis y-axis X-axis Y-axis | (in) (in) ICT- (gm- in in 04 4000 -400 DO 18 SO 500 500L D-500 -100 Tsa Total Torque 400 500 1-500 Total Torque (100 gm masses) (50 gm masses) 1 in) 100 100 -200 -200 |-400 -150 350 50 50 1 -10 -112 Total Torque (50 gm masses) Total Torque (100 gm masses) 400 500 -500 Total Torque (100 gm masses) 15 * 100 From the first table: Is the sum of the torques about either individual axis equal to zero? If not, where might the discrepancy exist? In Step 3: If the 100 gram mass remains where it is and a 200 gram mass replaces the 50 gram mass, where should the 200 gram mass be moved to achieve rotational equilibrium? B. Masses Suspended from Hangers | Mass Position Mass X Position y (in) (in) (sm) Torque About About x-axisy -axis gm- gm- in in) Torgue About About x-axis y-axis gm- gm- in in) (in) (in) 0 -3 900 3000S 2001 - 40 Total Torque Total Torque Total Torque 16 - 3 500 250 -7 -8 30 600 0 5 400 Total Torque C I C. Center of Gravity of a System of + Masses 1. Mass Position Position Torque | About About X-axis y-axis Mass (m) Torgue About About X-axis y-axis gm- gm- in) in) (in) (in) in in) 7,3 6.2 200 100 30 150 250 -7 -8 Total Torque 2. Determine the theoretical center of gravity for the 100, 150, and 250 gram masses. X. -2.9 -2.5 Theoretical x: -2.9 Theoretical y: -2.5 3. Find the percent error: Measured X:-2.9 in Measure y: -2.8 in % error in x: 0% % error in y: -12% Note: % error = 100 x (theory - measured/ theory) D. Center of Gravity of an Unknown Object 1. Mass of object: m=187 gm Mass Position 4.7 100 100 4.8 3. Calculate the center of gravity for the irregularly-shaped object. Remember to give units. Calculated Calculated you