Could someone please help me with this question. I am confused on how to get the point values based off -2

Equation: f(x) = -x^3 + 6x^2 + 20

20 is the y - intercept

Mort SC, delete home end num lock 8 9 O verr.num. 3 1/4 1/2 3/4 E Create a cubic function with 2 critical points at "nice "" x-values and a y- intercept of 20 . D make sure to choose your own O equation/ method with the daman ins adrage . * fix the very ( application question ) last part Choosen -D X = ( - 2, 10 ) [ working backwards ] - - 3 X ( x - 4 ) fi (x ) = - 3 X 2 + 1 2 X F (x ) = - x 3 + 6x 2 + 20 UD constant ] So the arsial equahin y - intercept Shall be: F (x ) = = x 3 + 6x * + 20 Knowing our y - intercept, we know that flor Shall equal to itsers