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Could you explain how to solve this, step by step? FLX ) Find the equation of the line tangent to f (x) = 2x -

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FLX ) Find the equation of the line tangent to f (x) = 2x - 5' at x = 2. Answer in point-slope form! (x ) = 2x - 5+ 4 x7451 5 quotient (4 points) q ( x ) rule ! ! ( X ) = 2 x - 5- 16xx 5 f ( x ) = 2x - 5+ 2 ( 2 ) - 5::. 4- 5 a(x )((x)- f( x)a'(x ) 24

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