Could you explain number 3 ? I don't understand how to compute the conditional probability for multiple events. I tried to do( 1-P(BC)+P(M)-P(MandBC)) X P(T) /P(T) and it does not give me the right answer.

According to a survey, 16% of the population in Canada is technology savvy. The figure changes by region. For example, in BC, the figure is 20% and in Manitoba the figure is 17%. Sixteen percent of Canadian population lives in BC and 3.7% in Manitoba. Suppose a Canadian is chosen at random. 1. What is the probability that the person lives in BC and is technology savvy? A) 2.5% B) 3.2% C) 4.2% D) 1.6% 2. Suppose the selected person in known not to be technology savvy. What is the probability that the person lives in Manitoba? A) 4.1% B) 3.7% C) 2.3% D) 1.8% 3. Suppose the selected person in known to be technology savvy. What is the probability that the person lives neither in BC nor in Manitoba? A) 48.5% B) 65.3% C C) 76.1% D) 84.7%