Could you provide a solution for problem 5.15 in the book that is titled "Computer Systems: A Programmer's Perspective (Third Edition)" by Bryant and O'Hallaron? The full text of problem 5.15 is provided below:

5.15

Please note, I have shared the full text of the problem, the full text of the problem that it references (below), and all diagrams associated with the reference problem. The Chegg expert has asked that I be more specific. I'm unsure of how to be more specific, because everything I have available related to this problem has been provided. If the experts can give me a more specific example of what would be helpful to them in answering the problem, please let me know and I will provide it. For example, if you still need me to be more specific, let me know which area of or aspect of the problem text that has been provided needs more clarification.

The Problem 5.15 above references another problem, 5.13. For reference, I've included the full test of problem 5.13 below. Please note that we do not need an answer for problem 5.13. I'm am copying and pasting all possible aspects of problem 5.15 for reference in case it may be helpful. The reference problem 5.13 is:

Write a version of the inner product procedure described in Problem 5.13 that uses 6 x 6 loop unrolling. Our measurements for this function with x86-64 give a CPE of 1.06 for integer data and 1.01 for floating-point data. What factor limits the performance to a CPE of 1.00? Suppose we wish to write a procedure that computes the inner product of two vectors u and v. An abstract version of the function has a CPE of 1418 with x86-64 and 26-29 with IA32 for integer, single-precision, and double-precision data. By doing the same sort of transformations we did to transform the abstract program combine1 into the more efficient combine4, we get the following code: 1 2 3 4 5 /* Inner product. Accumulate in temporary */ void inner4(vec_ptr u, vec-ptr v, data_t *dest) { long i; long length vec_length(); data_t *udata get_vec_start(u); data_t *vdata = get_vec_start(v); data_t sum = (data_t) 0; 6 7 8 9 10 11 for (i 0; i