Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

could you write the test bench code of this code? and can you edit the location of the swap code? please explain everything, thanks.(FFO MEMORY

could you write the test bench code of this code? and can you edit the location of the swap code? please explain everything, thanks.(FFO MEMORY N VHDL)

library IEEE; use IEEE.std_logic_1164.all; use IEEE.std_logic_unsigned.all; entity FIFO_LOGIC is generic (N: integer := 3); port (CLK, PUSH, POP, INIT: in std_logic; ADD: out std_logic_vector(N-1 downto 0); FULL, EMPTY, WE, NOPUSH, NOPOP: buffer std_logic); end entity FIFO_LOGIC; architecture RTL of FIFO_LOGIC is signal WPTR, RPTR: std_logic_vector(N-1 downto 0); signal LASTOP: std_logic; begin SYNC: process (CLK) begin if (CLK'event and CLK = '1') then if (INIT = '1') then -- initialization -- WPTR <= (others => '0'); RPTR <= (others => '0'); LASTOP <= '0'; elsif (POP = '1' and EMPTY = '0') then -- pop -- RPTR <= RPTR + 1; LASTOP <= '0'; elsif (PUSH = '1' and FULL = '0') then -- push -- WPTR <= WPTR + 1; LASTOP <= '1'; end if; -- otherwise all Fs hold their value -- end if; end process SYNC; COMB: process (PUSH, POP, WPTR, RPTR, LASTOP, FULL, EMPTY) begin -- full and empty flags -- if (RPTR = WPTR) then if (LASTOP = '1') then FULL <= '1'; EMPTY <= '0'; else FULL <= '0'; EMPTY <= '1'; end if; else FULL <= '0'; EMPTY <= '0'; end if; SEQUENTIAL LOGIC MODELING EXAMPLE USING 2-PROCESS MODELING STYLE C. E. Stroud, ECE Dept., Auburn Univ. 3 8/06 -- address, write enable and nopush/nopop logic -- if (POP = '0' and PUSH = '0') then -- no operation -- ADD <= RPTR; WE <= '0'; NOPUSH <= '0'; NOPOP <= '0'; elsif (POP = '0' and PUSH = '1') then -- push only -- ADD <= WPTR; NOPOP <= '0'; if (FULL = '0') then -- valid write condition -- WE <= '1'; NOPUSH <= '0'; else -- no write condition -- WE <= '0'; NOPUSH <= '1'; end if; elsif (POP = '1' and PUSH = '0') then -- pop only -- ADD <= RPTR; NOPUSH <= '0'; WE <= '0'; if (EMPTY = '0') then -- valid read condition -- NOPOP <= '0'; else NOPOP <= '1'; -- no red condition -- end if; else -- push and pop at same time if (EMPTY = 0) then -- valid pop -- ADD <= RPTR; WE <= '0'; NOPUSH <= '1'; NOPOP <= '0'; else ADD <= wptr; WE <= 1; NOPUSH <= 0; NOPOP <= 1; end if; end if; end process COMB; end architecture RTL;

----------swap------------------

begin output <= bubble0; process(clk) begin if rising_edge(clk) then if unsigned(input0) > unsigned(input1) then -- swap bubble1 <= input0; bubble0 <= input1; else bubble0 <= input0; bubble1 <= input1; end if; end if; end process; end Behavioral;

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

More Books

Students also viewed these Databases questions

Question

How do you add two harmonic motions having different frequencies?

Answered: 1 week ago