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Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is What is

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Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is What is (Fnet 3)x, the x-component of the net force exerted by these two charges on a third charge 93 = 49.5 nC placed between q1 and q2 at x3 = -1.125 m ? d2 Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in newtons to three significant figures. where K = 1 , and ATTEO View Available Hint(s) 60 = 8.854 x 10-12 C2 /(N . m2) is the permittivity of free space. Consider two point charges located on the x axis: VO ? one charge, q1 = -17.0 nC , is located at @1 = -1.650 m ; the second charge, q2 = 37.5 nC , is at the origin (x = 0). ( Fnet 3) x = Nx =-1.65012 X=-10125 m F32 X= 0 4-0.525 -12g 1. 125 from above figure . The Electric force on charge a, due to charge q, is F31 = K9391 0 . 525 ) 2 = 9X10 X 49.5X 17.0x15'8 (0.525) 2 $3 1 = 2 . 74 7 x 10 N along left simibroly. The Electors fore on change q, due to change ge is ( 1 . 125 ) 2 = 9 X10 x 19. 5 X 37. 5 X10' ( 1 -125) 2 = 1. 32X 10 N along left - . The nef resultant fare on charge 9, is F3 = Fait For = 1. 32 x 10 + 2. 747 x10 alongleft $3 = 4. 0( x 10) alongleft 5'= 406 * 10'N alongleft

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