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Crall and Whipple attached a fan to a cart placed on a level track and then released the cart. They made a position-versus-time graph (see
Crall and Whipple attached a fan to a cart placed on a level track and then released the cart. They made a position-versus-time graph (see figure below) and fit a curve to these data such that x = 0.036 m + (0.0080 m/s)t + (0.10 m/s2)t2. x (m) 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0.6 0.4 0.2 0.0 Let (s) 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 (a) Find the velocity as a function of time. (Use the following as necessary: t. Do not enter units in your answer.) V X = Graph the velocity as a function of time. Vx (m/s) Vx (m/s) 0.8 0.8 0.6 0.6 0.4 0.4 0.2 0.2 t (s) t (s) O 2 3 4 O 1 2 3 4(b) What is the shape of the velocity-versus-time graph? What do you expect the accelelation-versus-time graph to look like? Explain. I This answer has not been graded yet. (c) Find the acceleration as a function of time. (Use the following as necessary: t. Do not enter units in your answer.) ax: Graph the acceleration as a function of time. ax (W52) ax (W52) 0-30 0.30 0.25 {125 0.20 020 0.15 0.15 0.10 0.10 0.05 0.05 t(5} """"""""t(S) O 1 2 3 4 O 1 2 3 4 axmusz) , (S) 0'30 0.30 \"-25 0.25 0.20 0.20 0.15 0.15 0.10 0.10 [105 0.05 - - - - - - - - - - - - - - - - t (s) 1 2 3 4 \"X (W52)
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