Create a method called reallylonghex add

public ReallyLongHex add(ReallyLongHex rightOp)

{

return null;

}

this is how much I have so far

To help you out with the assignment, we have implemented the methods above for you, with comments. See the code in ReallyLongHex.java. public ReallyLongHex add (ReallyLongHex rightop) Return a NEW ReallyLongHex that is the sum of the current ReallyLongHex and the parameter ReallyLongHex, without altering the original values. For example: ReallyLongHex X = new ReallyLongHex ("123456789"); ReallyLongHex Y = new ReallyLongHex ("987654321"); ReallyLongHex Z; z = x.add (Y); System . out.println(X + " + " + Y + " = " + Z); should produce the output: 0x1 2 3 4 5 6789 + 0x987654321 0xAAAAAAAAA = Be careful to handle carries correctly and to process the nodes in the correct order. Since the numbers are stored with the most significant digit at the beginning, the add) method can be implemented by first reversing the chains then traversing both chains in a systematic way. This must be done efficiently using references to traverse the lists. In other words, you should start at the beginning of each ReallyLongHex and traverse one time while doing the addition. The KEY is that for add) (and subtract) you should access each Node in the list only 1 time TOTAL. This is true for other methods as well. Think