Create your assignment in your word processing program and when complete. click the open button below to upload your paper to your teacher. Please note that you may upload muitiple tiles where applicable. Remember to review the rubric before submitting to see how you will be graded. Introduction In the 1994 movie thriller \"Speed\Scenario 1 velocity of bus = 70 mph : 31 m/s = ( u ) Le1. from the clip , time taken = 8 seconds (approx ) 1. - component of the bus's Initial velocity. from the data , it has been given that the bus was traveling on the horizontal, so there is no angle . . The n- component of the bus = .speed of bus They are equal . 2- component of initial velocity = 31 m/s ( Answer ) 2. y- component of bus's mitial velocity, Let vy = y- component 9 Vy = u sino, But D = 0 ( no incline ) 9 vy = 31 m/s x sino = 31m/SXO = 0 9 / vy = 0 m/s |( Answer ) There is no y-component of initial velocity . 3. The bus was in the air for an approximate time of 8 seconds . ( Answer ) . 4. time t = 8s Let us consider-the motion along y-axis, initial velocity along y-axis = 0m/s (Uy)t= 8s, a = g= 9.8m/s2 ( acceleration due to gravity) let'sy be the vertical distance Using equation of motion Sy = uyt + + at2 = 0x8 +x 9.8 x 82 M 9 / sy = 0+ 313.6 m 9 Sy = 313. 6 m | CAnswer] the bus would have fallen 313.6 m before falling to the other side . 5. No, it. is not possible in this scenario, as The both sides are at same height. Scenario - 2 (8=50 ) Speed = 31 m /s = u 1 . y - component of initial velocity My = u sino Sin 5= 0.08 9 ly = 31 m /s x Sin 5 . [ My = 2.70 m/s / (Answer ) 2 . X- component of initial velocity Un = u coso = 31m/s x cos 5. 6035= 0.996 9 / ux = 30. 88 m/s ( Answer ) 3 . The bus was in the air for a time interval = 8 seconds ( approximately ). 4. Along vertical motion : - Now the bus has an initial speed in the 4 direction, My = 2.70 m/s ( to be considered negative) But a = q = 9.8 m/s? ( acceleration due to gravity t = 8 seconds initial velocity was considered negative equation of motion because it was opposite S = ut + + atz to direction of motion 9 sy = uyt + + at2 = - 2. 7x8 +_x9.8 x 82 m 2 ( - 21.6 + 313 . 6 ) m = 292 m 9 / Sy = 292 m / (Answer ) So, the bus would have fallen a vertical distance of 292 m before falling to the other side . 5 . No, even in this condition, the bus would not have landed safely