Current Balance Template Page 2 of 4 CURRENT APPARENT WEIGHT MAGNETIC FORCE (Amperes) (Newtons) Newtons O. S A JOSS N 0. 32 5 0. 8 AT 1. SS N D. ANN 1. 0 A 1. SS N OrSON 1. 3 A 1. SAN . 6 A 1. SAN 0 .62 x 1. 7 A 1. 5 4N 0. 71 N 4. Attach your plot of Magnetic Force vs. Current, from this data. 5. On the page with your graph, show how you got the slope of your graph. (If you used Excel, the equation for the fit line is sufficient.) Then, write the result for the slope in the space below. You must include units. 6. The slope of that line is equal to the rise over run, that is, the force per current (F/I). What combination of physical quantities (other than the obvious F/1) does the slope of that line represent? 7. Using the slope, calculate the strength of the magnetic field. Show all steps.Part 1: Force vs. Current Data: 3.2 cur Length of Wire in Current Loop: Actual Mass of the Magnet Assembly: 158. 2 + 0. 1 CURRENT APPARENT MASS WITH CURRENT (Amperes) (grams) 05 A $ 0. 01 A 157. 8 g = 0.016 0 . 6 A = 0.0 ) At 157. 76 9 = 0.01 9 1.0 A # 01 01 A 157. 70 A = 0. 019 1-3 ff 157. 64 % + 0101 8 = 0. 0 ) A 157. 58 9 = 0,019 1.9 A = 010 1 A 157 . 49 8 = 0101 9 Analysis: 1. Using the actual mass of the magnet assembly, calculate the actual weight of the magnet assembly, in Newtons. F = ( 0 . 1582 vg ) ( 9.8 ) = 15SN 2. Using the apparent mass of the magnet assembly (with some current running), show one sample calculation for finding the apparent weight of the magnet assembly, in Newtons. Fill in the results for the remaining currents, in the table on the next page. F = ( 0 . 15 78 * g ) ( 9. 8 ) = 1. SSN 3. Using the apparent weight and actual weight of the magnet assembly, show one sample calculation for finding the magnetic force on the magnet assembly, in Newtons. Fill in the results for the remaining currents, in the table on the next page. F = . L. B sin e ACE 491 - APeaseutt = 158. 280- 157.8 = 0.32 NPart 2: Force vs. Length of Wire Data: Actual Mass of the Magnet Assembly: APPARENT MASS LENGTH OF CURRENT CURRENT LOOP (cm) (Amperes) WITH CURRENT (g) 1. 2 I f 157. 89 2. 2 I A 15 7.78 8 3. 2 I A 157. 70 g 4 . 2 1 A 157. 65 6. 4 A 157. 49 A 157. 33 Analysis: 1. The goal was to keep the current exactly the same for all current loops; however, that is often difficult. So, calculate the average value of the current. 1 + 1 + 1 7 1 + 1 + = 1 A 2. Using the same methods as Part 1, calculate the apparent weight of, and the magnetic force on, the magnet assembly (in Newtons). Fill in the results in the table below. (No sample calculations are required, since they are the same as in Part 1.) LENGTH OF APPARENT WEIGHT MAGNETIC FORCE CURRENT LOOP (cm) Newtons (Newtons) 3. Attach your plot of Magnetic Force vs. Length of Wire, from this data.Actual Mass of the Magnet Assembly: + LENGTH OF CURRENT APPARENT MASS CURRENT LOOP (cm) (Amperes) WITH CURRENT (g) 1.2 157. 89 2. 2 I A 15 7. 78 8 3. 2 1 A 157. 70 9 4 - 2 1 A IS7. 6 5 6. 4 I A 157. 49 1 A 157. 33 Analysis: 1. The goal was to keep the current exactly the same for all current loops; however, that is often difficult. So, calculate the average value of the current. 1 + 1 + 1 + 1 + 1 + = 1 A 2. Using the same methods as Part 1, calculate the apparent weight of, and the magnetic force on, the magnet assembly (in Newtons). Fill in the results in the table below. (No sample calculations are required, since they are the same as in Part 1.) LENGTH OF APPARENT WEIGHT MAGNETIC FORCE CURRENT LOOP (cm) (Newtons) (Newtons Attach your plot of Magnetic Force vs. Length of Wire, from this data.Current Balance Template Page 4 of 4 4. On the page with your graph, show how you got the slope of your graph. (If you used Excel, the equation for the fit line is sufficient.) Then, write the result for the slope in the space below. You must include units. 5. The slope of that line is equal to the rise over run, that is, the force per length (F/L). What combination of physical quantities (other than the obvious F/L) does the slope of that line represent? 6. Using the slope, calculate the strength of the magnetic field. Show all steps. Conclusions: 1. By averaging the values obtained in Parts 1 and 2, calculate a best estimate for the magnetic field. Calculate the percentage difference between your values. 2. Given that the magnetic field of the earth is approximately 0.5 Gauss (1 Gauss = 10 *Tesla), how many times stronger is the magnetic field of the horseshoe magnets used in this experiment than that of the earth? 3. On the back of this page or on a separate page, make a sketch of your apparatus, indicating the direction that the current was flowing through your wire, the direction of the force on your wire, and which side of your magnet was red, vs. which side was white. (Using a perspective view, side view, and top view, as in the introduction of the handout, may be helpful. If you prefer, you may draw directly on top of them, as long as everything is labeled clearly.) Using these, use the right hand rule to determine the direction of the magnetic field for your magnet: is it from white to red, or red to white