Cybersecurity - Wireshark:

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Protocol Length Info DNS DNS TCP TCP TCP HTTP No. Time Source 140.192.38.112 140.192.36.3 140.192.38.112 140.192.36.128 140.192.38.112 140.192.38.112 140.192.36.128 140.192.36.128 140.192.38.112 140.192.36.128 140.192.36.128 140.192.38.112 Destination 140.192.36.3 140.192.38.112 140.192.36.128 140.192.38.112 140.192.36.128 140.192.36.128 140.192.38.112 140.192.38.112 140.192.36.128 140.192.38.112 140.192.38.112 140.192.36.128 80 Standard query 0x2ae0 A facweb.cs.depaul.edu 96 Standard query response 0x2aee A facweb.cs.depaul.edu A 140.192.36.128 66 62876 80 [SYN] Seq=0 Win=8192 Len=0 MSS=1460 WS-256 SACK-PERM=1 66 80 62876 [SYN, ACK] Seq=0 Ack-1 Win-8192 Len=0 MSS=1380 WS-256 SACK-PERMs] 54 62876 80 [ACK] Seq-1 Ack-1 Win-66048 Len-0 1 0.000000 2 0.001817 3 0.008058 4 0.009723 5 0.009817 6 0.053782 70.063461 8 0.063463 9 0.063525 10 0.063736 11 0.063736 12 0.063765 723 GET /brewster/it263/list.htm HTTP/1.1 1434 8062876 [ACK] Seq-1 Ack-670 Win 66048 Len-1380 [TCP segment of a reassembled PD] 1434 80 62876 [ACK] Seq=1381 Ack-670 win-66048 Len=1380 [TCP segment of a reassembled PDU] TCP TCP TCP HTTP TCP 54 62876 80 [ACK] Seq-670 Ack-2761 Win-66048 Len-0 1434 80 62876 [ACK] Seq-2761 Ack-670 win-66048 Len=1380 [TCP segment of a reassembled PDU] 1307 HTTP/1.1 200 OK (text/html) 54 62876 80 [ACK] Seq-670 Ack-5394 Win-66048 Len-0 3. What are the following values? Tell me these numeric values from the Wireshark file: a) (3 points) The IP address of my DNS Server. b) 3 points) The Ethemet MAC address of my Office Computer. c) (3 points) The private TCP port number associated with my browser window (3 points) What is the purpose of packets #3, #4 and #5? What do they accomplish? 4