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( d ) 2 points possible ( graded ) Since the convergence of the perceptron algorithm doesn't depend on the initialization, the end performance on
d
points possible graded
Since the convergence of the perceptron algorithm doesn't depend on the initialization, the end performance
on the training set must be the same. Are the resulting s the same regardless of the initialization?
Yes
No
Does this necessarily imply that the performance on a test set is the same?
Yes
No
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