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d Consider the integral: fm (9 :19) 2 What trig substitution is relevant here? 09: = 9tan(6) 09: = 93in(6) 03: = 3cos(9) 03: =

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d Consider the integral: fm (9 :19)\" 2 What trig substitution is relevant here? 09: = 9tan(6) 09: = 93in(6) 03: = 3cos(9) 03: = 33in(6) 03: = 3tan(9) Making this substitution, evaluating integral, and writing in terms of 3: results in: :]+0

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