(d) If C is the curve x = t, y = 3t + 1 for 0

(d) If C is the curve Evaluating this integral we obtain I = 1 = 21 t, y = 3t + 1 for 0 t 3, then I + y)d fab f(t)dt, where Solutions: Set = t, y 2t + 1, 0 t 3, so dT dt, and @ y)dc 4t + 1 dt So we obtain f(t) _ 2 . 32 + 3 21 (11) (12) (13) (14) (15) Parameterizations are not unique, so we could make other choices for a, b, and f, but regardless of what we choose we should get I = 21.