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Data Table 1: Angle 0 = 90, Vary Height of Canon H and Initial Velocity Voy Measure Time t reaching to maximum height Hmax
Data Table 1: Angle 0 = 90, Vary Height of Canon H and Initial Velocity Voy Measure Time t reaching to maximum height Hmax and Total Time t2. Calculate g value (g = Voy / t) and final velocity Vfy = Voy - g. t2 (use measured g value). Attach a screenshot of Simulation Data H = 15 m voy = 14 m/s to lab report. H (m) Voy (m/s) t1 (s) Hmax (m) t2 (s) g = Voy/t1 (m/s) Vfy (m/s) 7 15 1.53 18.47 3.47 9.80 -19.0 0 25 5 20 10 10 15 15 10 15 14 Question: 1) Why is the final velocity, Vfy, negative? 2) If object (last row of data) is launched vertically up with initial speed Voy = 14 m/s at height H=15 m, what is its time reaching maximum height, theoretically? What is its maximum height? Use g = 9.81 m/s. Please show here your work.
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