Data table You have been asked to evaluate the economic implications of various methods for cooling condenser effluents from a 200-MW steamelectric plant. There are two basic types of cooling towers: wet and dry. Furthermore, heat may be removed from condenser water by (1) forcing (mechanically) air through the tower or (2) allowing heat transfer to occur by making use of natural draft. Consequently, there are four basic cooling tower designs that could be considered. Assuming that the cost of capital to the utility company is 12% per year, your job is to recommend the best alternative (i.e., the least expensive during the service life). Further, assume that each alternative is capable of satisfactorily removing waste heat from the condensers of a 200-MW power plant. What noneconomic factors can you identify that might also play a role in the decision-making process? Click the icon to view the alternatives description. Click the icon to view the interest and annuity table for discrete compounding when i=12% per year. \begin{tabular}{|c|c|c|c|c|c|c|} \hline \multicolumn{7}{|c|}{ Discrete Compounding; i=12%} \\ \hline & \multicolumn{2}{|c|}{ Single Payment } & \multicolumn{4}{|c|}{ Uniform Series } \\ \hline & \begin{tabular}{l} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{c} Present \\ Worth Factor \end{tabular} & \begin{tabular}{c} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{c} Present \\ Worth Factor \end{tabular} & \begin{tabular}{l} Sinking \\ Fund \\ Factor \end{tabular} & \begin{tabular}{c} Capital \\ Recovery \\ Factor \end{tabular} \\ \hlineN & \begin{tabular}{c} To Find F \\ Given P \\ FiP \end{tabular} & \begin{tabular}{c} To Find P \\ Glven F \\ P/F \end{tabular} & \begin{tabular}{c} To Find F \\ Given A \\ F/A \end{tabular} & \begin{tabular}{c} To Find P \\ Given A \\ P/A \end{tabular} & \begin{tabular}{c} To Find A \\ Given F \\ A/F \end{tabular} & \begin{tabular}{c} To Find A \\ Given P \\ AMP \end{tabular} \\ \hline 1 & 1.1200 & 0.8929 & 1.0000 & 0.8929 & 1.0000 & 1.1200 \\ \hline 2 & 1.2544 & 0.7972 & 2.1200 & 1.6901 & 0.4717 & 0.5917 \\ \hline 3 & 1.4049 & 0.7118 & 3.3744 & 2.4018 & 0.2963 & 0.4163 \\ \hline 4 & 1.5735 & 0.6355 & 4.7790 & 3.0373 & 0.2092 & 0.3292 \\ \hline 5 & 1.7623 & 0.5674 & 6.3528 & 3.6049 & 0.1574 & 0.2774 \\ \hline 6 & 1.9739 & 0.5066 & 8.1152 & 4.1114 & 0.1232 & 0.2432 \\ \hline 7 & 2.2107 & 0.4523 & 10.0890 & 4.5638 & 0.0991 & 0.2191 \\ \hline s & 2.4760 & 0.4039 & 12.2997 & 4.9676 & 0.0013 & 0.2013 \\ \hline 9 & 2.7731 & 0.3606 & 14.7757 & 5.3242 & 0.0677 & 0.1877 \\ \hline 10 & 3.1069 & 0.3220 & 17.5487 & 5.6602 & 0.0570 & 0.1770 \\ \hline 11 & 3.4785 & 0.2875 & 20.6546 & 5.9377 & 0.0484 & 0.1684 \\ \hline 12 & 3.8960 & 0.2667 & 24. 1331 & 6.1944 & 0.0414 & 0.1614 \\ \hline 13 & 4.36035 & 0.2292 & 28.0291 & 6.4235 & 0.0357 & 0.1557 \\ \hline 14 & 4.8871 & 0.2046 & 32.3926 & 6.6242 & 0.0309 & 0.1500 \\ \hline 15 & 5.4736 & 0.1827 & 37.2797 & 6.8109 & 0.0268 & 0.1468 \\ \hline 16 & 6.1304 & 0.1631 & 42.7533 & 6.9740 & 0.0234 & 0.1434 \\ \hline 17 & 6.0060 & 0.1456 & 48.8837 & 7.1196 & 0.0205 & 0.1406 \\ \hline 18 & 7.6500 & 0.1300 & 66.7497 & 7.2497 & 0.0179 & 0.1379 \\ \hline 19 & 8.612B & 0.1161 & 63.4397 & 7.3659 & 0.0158 & 0.1368 \\ \hline 20 & 9.6463 & 0.1037 & 72.0524 & 7.4694 & 0.0139 & 0.1339 \\ \hline 21 & 10.8036 & 0.0826 & 81.6987 & 7.5620 & 0.0122 & 0.1322 \\ \hline 22 & 12.1003 & 0.0826 & 92.5026 & 7.6446 & 0.0108 & 0.1308 \\ \hline 23 & 13.5623 & 0.0738 & 104.6029 & 7.7184 & 0.0096 & 0.1296 \\ \hline 24 & 15.1796 & 0.0659 & 118.1562 & 7.7843 & 0.0085 & 0.1285 \\ \hline 28 & 17.0001 & 0.0688 & 133.3309 & 7.8431 & 0.0075 & 0.1275 \\ \hline 30 & 29.9699 & 0.0034 & 241.3327 & 8.0652 & 0.0041 & 0.1241 \\ \hline 35 & 52.7996 & 0.0189 & 431.6635 & 8.1755 & 0.0023 & 0.1223 \\ \hline 40 & 93.0610 & 0.0107 & 767.0914 & 8.2439 & 0.0013 & 0.1213 \\ \hline 45 & 163.5876 & 0.0061 & 1369.2300 & 8.2825 & 0.0007 & 0.1207 \\ \hline 80 & 289.0022 & 0.0035 & 2400.0182 & 8.3045 & 0.0004 & 0.1204 \\ \hline \end{tabular} The AW of Wet Tower, Mechanical Dratt is The AW of Wet Tower, Natural Draft is $ The AW of Dry Tower, Mechanical Draft is The AW of Dry Tower, Natural Draft is \$ Data table You have been asked to evaluate the economic implications of various methods for cooling condenser effluents from a 200-MW steamelectric plant. There are two basic types of cooling towers: wet and dry. Furthermore, heat may be removed from condenser water by (1) forcing (mechanically) air through the tower or (2) allowing heat transfer to occur by making use of natural draft. Consequently, there are four basic cooling tower designs that could be considered. Assuming that the cost of capital to the utility company is 12% per year, your job is to recommend the best alternative (i.e., the least expensive during the service life). Further, assume that each alternative is capable of satisfactorily removing waste heat from the condensers of a 200-MW power plant. What noneconomic factors can you identify that might also play a role in the decision-making process? Click the icon to view the alternatives description. Click the icon to view the interest and annuity table for discrete compounding when i=12% per year. \begin{tabular}{|c|c|c|c|c|c|c|} \hline \multicolumn{7}{|c|}{ Discrete Compounding; i=12%} \\ \hline & \multicolumn{2}{|c|}{ Single Payment } & \multicolumn{4}{|c|}{ Uniform Series } \\ \hline & \begin{tabular}{l} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{c} Present \\ Worth Factor \end{tabular} & \begin{tabular}{c} Compound \\ Amount \\ Factor \end{tabular} & \begin{tabular}{c} Present \\ Worth Factor \end{tabular} & \begin{tabular}{l} Sinking \\ Fund \\ Factor \end{tabular} & \begin{tabular}{c} Capital \\ Recovery \\ Factor \end{tabular} \\ \hlineN & \begin{tabular}{c} To Find F \\ Given P \\ FiP \end{tabular} & \begin{tabular}{c} To Find P \\ Glven F \\ P/F \end{tabular} & \begin{tabular}{c} To Find F \\ Given A \\ F/A \end{tabular} & \begin{tabular}{c} To Find P \\ Given A \\ P/A \end{tabular} & \begin{tabular}{c} To Find A \\ Given F \\ A/F \end{tabular} & \begin{tabular}{c} To Find A \\ Given P \\ AMP \end{tabular} \\ \hline 1 & 1.1200 & 0.8929 & 1.0000 & 0.8929 & 1.0000 & 1.1200 \\ \hline 2 & 1.2544 & 0.7972 & 2.1200 & 1.6901 & 0.4717 & 0.5917 \\ \hline 3 & 1.4049 & 0.7118 & 3.3744 & 2.4018 & 0.2963 & 0.4163 \\ \hline 4 & 1.5735 & 0.6355 & 4.7790 & 3.0373 & 0.2092 & 0.3292 \\ \hline 5 & 1.7623 & 0.5674 & 6.3528 & 3.6049 & 0.1574 & 0.2774 \\ \hline 6 & 1.9739 & 0.5066 & 8.1152 & 4.1114 & 0.1232 & 0.2432 \\ \hline 7 & 2.2107 & 0.4523 & 10.0890 & 4.5638 & 0.0991 & 0.2191 \\ \hline s & 2.4760 & 0.4039 & 12.2997 & 4.9676 & 0.0013 & 0.2013 \\ \hline 9 & 2.7731 & 0.3606 & 14.7757 & 5.3242 & 0.0677 & 0.1877 \\ \hline 10 & 3.1069 & 0.3220 & 17.5487 & 5.6602 & 0.0570 & 0.1770 \\ \hline 11 & 3.4785 & 0.2875 & 20.6546 & 5.9377 & 0.0484 & 0.1684 \\ \hline 12 & 3.8960 & 0.2667 & 24. 1331 & 6.1944 & 0.0414 & 0.1614 \\ \hline 13 & 4.36035 & 0.2292 & 28.0291 & 6.4235 & 0.0357 & 0.1557 \\ \hline 14 & 4.8871 & 0.2046 & 32.3926 & 6.6242 & 0.0309 & 0.1500 \\ \hline 15 & 5.4736 & 0.1827 & 37.2797 & 6.8109 & 0.0268 & 0.1468 \\ \hline 16 & 6.1304 & 0.1631 & 42.7533 & 6.9740 & 0.0234 & 0.1434 \\ \hline 17 & 6.0060 & 0.1456 & 48.8837 & 7.1196 & 0.0205 & 0.1406 \\ \hline 18 & 7.6500 & 0.1300 & 66.7497 & 7.2497 & 0.0179 & 0.1379 \\ \hline 19 & 8.612B & 0.1161 & 63.4397 & 7.3659 & 0.0158 & 0.1368 \\ \hline 20 & 9.6463 & 0.1037 & 72.0524 & 7.4694 & 0.0139 & 0.1339 \\ \hline 21 & 10.8036 & 0.0826 & 81.6987 & 7.5620 & 0.0122 & 0.1322 \\ \hline 22 & 12.1003 & 0.0826 & 92.5026 & 7.6446 & 0.0108 & 0.1308 \\ \hline 23 & 13.5623 & 0.0738 & 104.6029 & 7.7184 & 0.0096 & 0.1296 \\ \hline 24 & 15.1796 & 0.0659 & 118.1562 & 7.7843 & 0.0085 & 0.1285 \\ \hline 28 & 17.0001 & 0.0688 & 133.3309 & 7.8431 & 0.0075 & 0.1275 \\ \hline 30 & 29.9699 & 0.0034 & 241.3327 & 8.0652 & 0.0041 & 0.1241 \\ \hline 35 & 52.7996 & 0.0189 & 431.6635 & 8.1755 & 0.0023 & 0.1223 \\ \hline 40 & 93.0610 & 0.0107 & 767.0914 & 8.2439 & 0.0013 & 0.1213 \\ \hline 45 & 163.5876 & 0.0061 & 1369.2300 & 8.2825 & 0.0007 & 0.1207 \\ \hline 80 & 289.0022 & 0.0035 & 2400.0182 & 8.3045 & 0.0004 & 0.1204 \\ \hline \end{tabular} The AW of Wet Tower, Mechanical Dratt is The AW of Wet Tower, Natural Draft is $ The AW of Dry Tower, Mechanical Draft is The AW of Dry Tower, Natural Draft is \$