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def diff_sum_square_and_square_sum(n): sum_square = sum(map(lambda x: x*x, range(0, int(n+1)))) square_sum = sum(range(0, int(n + 1))) **2 diff = square_sum - sum_square return diff n =
def diff_sum_square_and_square_sum(n): sum_square = sum(map(lambda x: x*x, range(0, int(n+1)))) square_sum = sum(range(0, int(n + 1))) **2 diff = square_sum - sum_square return diff n = int(input("enter your value n: ")) print(diff_sum_square_and_square_sum(n))
this is the function i have but i cant get reduce () and operator to work
Rewrite the previous function, use reduce0 with operator.add to add all items together instead of sum0. Try to use list comprehensions also if needed so that you can calculate the sum of squares in one line of code. One way for example is something like: Sumofsquares- reduce(operator.add,)Step by Step Solution
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