def invert_bdm(bdm):

'''(dict of {str:dict of {int:list of str}}) -> dict of {str:list of [str, int]}

Given bdm, a birthday month dictionary, return the equivalent birthday dictionary where keys are birthmonths and values are dictionaries that have keys as dates and values as list of names with people whose birthday is on that date. See section 1.2 of the related handout for more information.

>>> d = {"Jan": {1: ["Steve"], 5: ["Bob"]},

"Aug": {24: ["Sadia", "Tony"]}}

>>> d2 = invert_bdm(d)

>>> {"Steve": ["Jan", 1], "Bob": ["Jan", 5], "Tony": ["Aug", 24], "Sadia": ["Aug", 24]} '''

handout section 1.2

1.2 Question 2 Like a birthday month dictionary, a birthday dictionary also contains information about birthdays, but in a different format. The keys are peoples names and the values are 2- item lists describing those peoples birthdays. The first item in each list is the name of a month (a str) and the second is the day of that month (an int). For example, the following equivalent birthday dictionary has the same content, although in a different format, as the birthday month dictionary above.

{Ed: [May, 8], Peter: [May, 8],

Catherine: [February, 13], Katie: [May, 3]}

Complete the following function according to its docstring. Assume that each persons name in bdm is unique (i.e. not repeated in multiple months).

def invert_bdm(bdm):

(dict of {str:dict of {int:list of str}}) ->

dict of {str:list of [str, int]}

bdm is a birthday month dictionary. Return the equivalent birthday dictionary.