Demand less than Supply From \\To W1 W2 W3 W4 Total Supply F1 400 500 350 0 120 75 45 F2 250 300 250 0 85 30 55 F3 350 500 450 0 95 55 40 Total Demand 75 75 110 40 300 .The initial feasible solution is . f(min)=350(110)+0(10)+250(10)+300(75)+350(65)+0(30)=P86,250 Find the optimal solution by Modified Distribution Method