..depaul.edu/.../SSR_STUDENT_FL.SSR_MD_... Review PROBLEM-SOLVING STRATEGY 25.1 Conservation of energy in charge interactions Learning Goal: MODEL: Check whether there are any dissipative forces that would prevent the mechanical energy from being conserved. To practice Problem-Solving Strategy 25.1 for charge interaction problems. VISUALIZE: Draw a before-and-after pictorial representation. Define symbols that will be used in the problem, list known values, and identify what you are trying to find. A proton and an alpha particle are momentarily at rest at a distance r from each other. They then begin to move apart. Find the speed of the proton by the time the distance SOLVE: The mathematical representation is based off the law of conservation of mechanical energy: between the proton and the alpha particle doubles. Kr+ qVi = Kirt qVi. Both particles are positively charged. The charge and the mass of the proton are. respectively, e and m. The charge and the mass of the alpha particle are, respectively, Is the electric potential given in the problem statement? If not, you'll need to use a known potential, such as that of a point charge, or calculate the potential using the procedure given in Problem- 2e and 4m. Solving Strategy 25.2. Kr and Ki are the sums of kinetic energies of all moving particles. . Some problems may need additional conservation laws, such as conservation of charge or conservation of momentum. REVIEW: Check that your result has the correct units and significant figures, is reasonable, and answers the question. Mode The particles described in this problem interact under the effect of the electric force, which is a conservative force, so the system's mechanical energy is conserved. Visualize Part A Solve Part B Find the speed of the proton (ur )p by the time the distance between the particles doubles. Express your answer in terms of some or all of the quantities e, m, r, and co- View Available Hint(s) AEQ x x 8 Vx Vx x x 1X X.10 8 ke2 (uf )P 5 rm The correct answer does not depend on: ke. No credit lost. Try again Submit Previous Answers