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Describe the error in the following proof that 0 1 is not a regular language ( an error must exist because 0 1 is regular
Describe the error in the following proof that is not a regular language
an error must exist because is regular The proof is by contradiction.
Assume is regular.
Let p be the pumping length for given by the pumping lemma.
Choose s to be the string pp
We know that s is a member of but a previous proof shows that s cannot
be pumped.
Thus there is a contradiction. So is not regular.
This is demonstrated both in example in your textbook and in example of the
Pumping Lemma lecture slides on Canvas
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