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Describe the error in the following proof that 0 1 is not a regular language ( an error must exist because 0 1 is regular

Describe the error in the following proof that 01 is not a regular language
(an error must exist because 01 is regular). The proof is by contradiction.
Assume 01 is regular.
Let p be the pumping length for 01 given by the pumping lemma.
Choose s to be the string 0p1p.
We know that s is a member of 01, but a previous proof shows that s cannot
be pumped.
Thus there is a contradiction. So 01 is not regular.
This is demonstrated both in example 1.73 in your textbook and in example 1 of the
Pumping Lemma lecture slides on Canvas

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