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Design a bridge girder 27.0m in length and will carry a super-imposed dead load of w(DL) = 15.50 kN/m and live load of w(LL) =
Design a bridge girder 27.0m in length and will carry a super-imposed dead load of w(DL) = 15.50 kN/m and live load of w(LL) = 14.46 kN/m.
Use AASHTO Type IV-B Girder.
What would be the design eccentricity (e) at the midspan and at the ends of the girder such that all allowable stress limits for transfer, initial and service are met? Hint: Initial e can be taken from the kern formula for AASTO Girders e = r2/c
Prestress Data: Pi = 4633.59 kN Pe = 4238 kN
Concrete Data: fe=35MPa (5000psi) Fci-28MPa (4000 psi)
\begin{tabular}{|lll|} \hline \multicolumn{3}{|c|}{ AASHTO Type IV-B Property } \\ \hline Property & Ends & Midspan \\ \hline Ix (Inertia) mm4 & 1.801011 & 1.701011 \\ \hline Area (m2) & 0.836 & 0.611 \\ \hline R2 (m2) & 0.2161 & 0.2777 \\ \hline Sx (top) m3 & 0.2215 & 0.2112 \\ \hline Sx (bot) m3 & 0.23854 & 0.22047 \\ \hline Ctop (m) & 0.816 & 0.803 \\ \hline Cbot (m) & 0.757 & 0.770 \\ \hline \end{tabular} \begin{tabular}{|lll|} \hline \multicolumn{3}{|c|}{ AASHTO Type IV-B Property } \\ \hline Property & Ends & Midspan \\ \hline Ix (Inertia) mm4 & 1.801011 & 1.701011 \\ \hline Area (m2) & 0.836 & 0.611 \\ \hline R2 (m2) & 0.2161 & 0.2777 \\ \hline Sx (top) m3 & 0.2215 & 0.2112 \\ \hline Sx (bot) m3 & 0.23854 & 0.22047 \\ \hline Ctop (m) & 0.816 & 0.803 \\ \hline Cbot (m) & 0.757 & 0.770 \\ \hline \end{tabular}Step by Step Solution
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