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det A = 5 (1) (2) (3) (4) A = (5 (6) 120 140 165 -140 -165 NP det A = ON 2 AF LWNN
det A = 5 (1) (2) (3) (4) A = (5 (6) 120 140 165 -140 -165 NP det A = ON 2 AF LWNN NWWN (2) (3) (4) (5) (6) 12 -8 36 -12 -10 NP The sum of elements of the first two rows of the matrix 4" is equal to W -5 2 (D) (2 -1 4 (3) (4) (5 (6) 3 A= 2 4 0.114 -0.114 1.014 -1.014 4.101 NP 3x-5y+2z =14, XV = -x+4y+42 =-21, (1) (4) 5x + 2y+4z =-9. 4 (2) (3) (5) (6 4 9 -g 6 NP The sum of all elements of the matrix X is equal 5 (1) (2) (3) (4 (5) (6) 2 10 3 7 -11 NP -5 2 2 10 -17 The sum of all elements of the matrix X is equal -1 4 4 . X + 4 3 = - 26 14 (2) (3) (4) (5) (6) 2 4 -15 13 13 -2 0 10 -7 NP General solution of the system is of the * -X2 - 2.x3 + 2x, =-2, form (a, +hx, +qx , a, +hex, + c,x,, x, , x, ). 3.x, + 3x, - 2x, - x, =3, *j,x, e (-oo, oo) . Then a, +h, + + a, +h, + c, is equal (7x, +1 1x, - 2x, - 7x, = 13. (1) (2) (3) 1(4) (5) (6) 3 2 -1 NP Let AX"B" = C. The sum of all elements of matrix X is equal to 8 (1) (2) (3) (4) (5) -5.500 -5.000 -4.500 -4.000 -3.500A(1;5;-3) B(3;5;-2) C(4;4;4) D(2;-1;1) The angle CBD in degrees is equal to (1) (2) (3) (4) (5) (6) 56.625 56.231 56.844 56.115 56.801 NP The distance from the point P(1; 1; 1) to the plain BCD is equal to 2 (1) (2) (3) (4) (5) (6) 0.215 0.345 0.884 1.461 1.685 NP The distance from the point D to the line BC is equal to (1) (2) (3) (4) (5) (6) 5.625 5.215 5.324 5.715 5.664 NP Let I be the volume of pyramid ABCD, HA- the length of its altitude dropped from the vertex A. Then V . H is equal to 4 (1) (2) (3) (4) (5) (6) 16.221 16.324 16.524 16.684 16.758 NP Let projection of the vertex A of the pyramid ABCD onto the plane BCD be a point with coordinates (X., yo, Zo) . Then the sum x, + yo + z, is equal to 5 (1) (2) (3) (4) (5) (6) 3.224 -3.324 -4.241 4.235 3.823 NP
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