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detailed solution 6-7. 2-value for 16, 23: Corresponding probability, P (Z >4): 10. Probability that the customer will have to wait less than 16 mins

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6-7. 2-value for 16, 23: Corresponding probability, P (Z >4): 10. Probability that the customer will have to wait less than 16 mins or more than 23 mins:Question 7 4 pts Part 4. Consider the following problem: A mandatory competency test for high school sophomores has a normal distribution with a mean of 450 and a standard deviation of 90. Round off z-values to two decimal places. Report the scores as whole numbers. A top 3% of students receive PhP 25,000. What is the minimum score you would need to receive this award? 1. z-value corresponding to top 3%: 2. The minimum score you would need to receive the award:Question 8 6 pts Part 5. Consider the following problem: The average number of pounds of meat that a person consumes per year is 216.4 lbs. Assume that the variance is 635.2 Ibs and the distribution is approximately normal. Round off 2-values to two decimal places. Express probabilities in 4 decimal places as found in the provided Z-table (Table 1 The Standard Normal Distribution--uploaded on Canvas). Part 5.1. Find the probability that a person selected at random consumes less than 225 lbs per year. 1. z-value: 2. Probability: Part 5.2. If a sample of 35 individuals is selected, find the probability that the mean of the sample will be less than 225 Ibs per year. 3. 2-value: 4. Probability:Part 3. Consider the following problem: The average waiting time to be seated for dinner at a popular restaurant is 22.4 minutes, with a standard deviation of 2.8 minutes. Assume the variable is normally distributed. Round off z-values to two decimal places. Express probabilities in 4 decimal places as found in the provided z-table (Table 1 The Standard Normal Distribution--uploaded on Canvas). Include a leading zero before the decimal point, e.g. "0.9999" and not ".9999". When a customer arrives at the restaurant for dinner, answer the following questions: Part 3.1. Find the probability that the customer will have to wait between 14 and 20 minutes: 1-2. z-value for 14, z1 : corresponding probability. P (Z 1 ): 3-4. z-value for 20, z2: corresponding probability, P (Z

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